-24x^2-39x+18=0

Solution for -24x^2-39x+18=0 equation:

-24x^2-39x+18=0

a = -24; b = -39; c = +18;
Δ = b2-4ac
Δ = -392-4·(-24)·18
Δ = 3249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3249}=57$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-39)-57}{2*-24}=\frac{-18}{-48}
=3/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-39)+57}{2*-24}=\frac{96}{-48}
=-2
$